Base | Representation |
---|---|
bin | 11001001111010010110000… |
… | …110000000111011010101011 |
3 | 112120000200211012212110221012 |
4 | 121033102300300013122223 |
5 | 104022124300122414011 |
6 | 1032025354424534135 |
7 | 32244431343631136 |
oct | 3117226060073253 |
9 | 476020735773835 |
10 | 111002100201131 |
11 | 324067a98212a7 |
12 | 10548b4a92134b |
13 | 49c25b76c8559 |
14 | 1d5a75d28721d |
15 | cc7645530a8b |
hex | 64f4b0c076ab |
111002100201131 has 2 divisors, whose sum is σ = 111002100201132. Its totient is φ = 111002100201130.
The previous prime is 111002100201061. The next prime is 111002100201151. The reversal of 111002100201131 is 131102001200111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111002100201131 - 222 = 111002096006827 is a prime.
It is a super-2 number, since 2×1110021002011312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111002100201151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55501050100565 + 55501050100566.
It is an arithmetic number, because the mean of its divisors is an integer number (55501050100566).
Almost surely, 2111002100201131 is an apocalyptic number.
111002100201131 is a deficient number, since it is larger than the sum of its proper divisors (1).
111002100201131 is an equidigital number, since it uses as much as digits as its factorization.
111002100201131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 111002100201131 its reverse (131102001200111), we get a palindrome (242104101401242).
The spelling of 111002100201131 in words is "one hundred eleven trillion, two billion, one hundred million, two hundred one thousand, one hundred thirty-one".
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