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11100270113 is a prime number
BaseRepresentation
bin10100101011010000…
…01010111000100001
31001122121010010222022
422111220022320201
5140213132120423
65033245151225
7542034511352
oct122550127041
931577103868
1011100270113
1147868a4259
12219955b515
13107b93408a
14774331d29
1544e798dc8
hex295a0ae21

11100270113 has 2 divisors, whose sum is σ = 11100270114. Its totient is φ = 11100270112.

The previous prime is 11100270109. The next prime is 11100270121. The reversal of 11100270113 is 31107200111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10938649744 + 161620369 = 104588^2 + 12713^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100270113 - 22 = 11100270109 is a prime.

It is a super-2 number, since 2×111002701132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11100270091 and 11100270100.

It is not a weakly prime, because it can be changed into another prime (11100273113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550135056 + 5550135057.

It is an arithmetic number, because the mean of its divisors is an integer number (5550135057).

Almost surely, 211100270113 is an apocalyptic number.

It is an amenable number.

11100270113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100270113 is an equidigital number, since it uses as much as digits as its factorization.

11100270113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42, while the sum is 17.

Adding to 11100270113 its reverse (31107200111), we get a palindrome (42207470224).

The spelling of 11100270113 in words is "eleven billion, one hundred million, two hundred seventy thousand, one hundred thirteen".