111003104417 has 2 divisors, whose sum is σ = 111003104418. Its totient is φ = 111003104416.

The previous prime is 111003104363. The next prime is 111003104423. The reversal of 111003104417 is 714401300111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101962707856 + 9040396561 = 319316^2 + 95081^2 .

It is an emirp because it is prime and its reverse (714401300111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111003104417 - 2¹⁴ = 111003088033 is a prime.

It is a super-2 number, since 2×111003104417² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111003104392 and 111003104401.

It is not a weakly prime, because it can be changed into another prime (111003104117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55501552208 + 55501552209.

It is an arithmetic number, because the mean of its divisors is an integer number (55501552209).

Almost surely, 2^111003104417 is an apocalyptic number.

It is an amenable number.

111003104417 is a deficient number, since it is larger than the sum of its proper divisors (1).

111003104417 is an equidigital number, since it uses as much as digits as its factorization.

111003104417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 111003104417 its reverse (714401300111), we get a palindrome (825404404528).

The spelling of 111003104417 in words is "one hundred eleven billion, three million, one hundred four thousand, four hundred seventeen".