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11100331414 = 25550165707
BaseRepresentation
bin10100101011010000…
…11001110110010110
31001122121020021001201
422111220121312112
5140213141101124
65033250343114
7542035155154
oct122550316626
931577207051
1011100331414
114786936317
12219958aa9a
13107b955c53
1477434a3d4
1544e7ac144
hex295a19d96

11100331414 has 4 divisors (see below), whose sum is σ = 16650497124. Its totient is φ = 5550165706.

The previous prime is 11100331397. The next prime is 11100331423. The reversal of 11100331414 is 41413300111.

11100331414 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 11100331391 and 11100331400.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2775082852 + ... + 2775082855.

It is an arithmetic number, because the mean of its divisors is an integer number (4162624281).

Almost surely, 211100331414 is an apocalyptic number.

11100331414 is a deficient number, since it is larger than the sum of its proper divisors (5550165710).

11100331414 is an equidigital number, since it uses as much as digits as its factorization.

11100331414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5550165709.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11100331414 its reverse (41413300111), we get a palindrome (52513631525).

The spelling of 11100331414 in words is "eleven billion, one hundred million, three hundred thirty-one thousand, four hundred fourteen".

Divisors: 1 2 5550165707 11100331414