11100333113 has 2 divisors, whose sum is σ = 11100333114. Its totient is φ = 11100333112.

The previous prime is 11100333059. The next prime is 11100333131. The reversal of 11100333113 is 31133300111.

Together with next prime (11100333131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9052951609 + 2047381504 = 95147^2 + 45248^2 .

It is an emirp because it is prime and its reverse (31133300111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11100333113 - 2²⁴ = 11083555897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11100333091 and 11100333100.

It is not a weakly prime, because it can be changed into another prime (11100333173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550166556 + 5550166557.

It is an arithmetic number, because the mean of its divisors is an integer number (5550166557).

Almost surely, 2^11100333113 is an apocalyptic number.

It is an amenable number.

11100333113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100333113 is an equidigital number, since it uses as much as digits as its factorization.

11100333113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11100333113 its reverse (31133300111), we get a palindrome (42233633224).

The spelling of 11100333113 in words is "eleven billion, one hundred million, three hundred thirty-three thousand, one hundred thirteen".