Base | Representation |
---|---|
bin | 110011101100001100… |
… | …0010011111001111001 |
3 | 101121112002102111211212 |
4 | 1213120120103321321 |
5 | 3304314113342131 |
6 | 122554510132505 |
7 | 11006536056404 |
oct | 1473030237171 |
9 | 347462374755 |
10 | 111004434041 |
11 | 43093122296 |
12 | 1961b1b1135 |
13 | a61062a387 |
14 | 5530766d3b |
15 | 2d4a3a2a2b |
hex | 19d8613e79 |
111004434041 has 2 divisors, whose sum is σ = 111004434042. Its totient is φ = 111004434040.
The previous prime is 111004434011. The next prime is 111004434053. The reversal of 111004434041 is 140434400111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78640424041 + 32364010000 = 280429^2 + 179900^2 .
It is a cyclic number.
It is not a de Polignac number, because 111004434041 - 210 = 111004433017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111004433998 and 111004434016.
It is not a weakly prime, because it can be changed into another prime (111004434011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55502217020 + 55502217021.
It is an arithmetic number, because the mean of its divisors is an integer number (55502217021).
Almost surely, 2111004434041 is an apocalyptic number.
It is an amenable number.
111004434041 is a deficient number, since it is larger than the sum of its proper divisors (1).
111004434041 is an equidigital number, since it uses as much as digits as its factorization.
111004434041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 111004434041 its reverse (140434400111), we get a palindrome (251438834152).
The spelling of 111004434041 in words is "one hundred eleven billion, four million, four hundred thirty-four thousand, forty-one".
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