Base | Representation |
---|---|
bin | 10100101011010101… |
… | …11111011111010001 |
3 | 1001122122111201201211 |
4 | 22111222333133101 |
5 | 140213324303443 |
6 | 5033313100121 |
7 | 542044012162 |
oct | 122552773721 |
9 | 31578451654 |
10 | 11101009873 |
11 | 478725a028 |
12 | 2199857641 |
13 | 107bb329c5 |
14 | 774485769 |
15 | 44e89319d |
hex | 295abf7d1 |
11101009873 has 2 divisors, whose sum is σ = 11101009874. Its totient is φ = 11101009872.
The previous prime is 11101009861. The next prime is 11101009919. The reversal of 11101009873 is 37890010111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7995399889 + 3105609984 = 89417^2 + 55728^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11101009873 is a prime.
It is a super-2 number, since 2×111010098732 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11101009273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550504936 + 5550504937.
It is an arithmetic number, because the mean of its divisors is an integer number (5550504937).
Almost surely, 211101009873 is an apocalyptic number.
It is an amenable number.
11101009873 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101009873 is an equidigital number, since it uses as much as digits as its factorization.
11101009873 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 31.
Adding to 11101009873 its reverse (37890010111), we get a palindrome (48991019984).
The spelling of 11101009873 in words is "eleven billion, one hundred one million, nine thousand, eight hundred seventy-three".
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