Base | Representation |
---|---|
bin | 11001001111011010001101… |
… | …101101000001011000011011 |
3 | 112120001110110212220011210012 |
4 | 121033122031231001120123 |
5 | 104022242142120401021 |
6 | 1032033200433512135 |
7 | 32245133550061421 |
oct | 3117321555013033 |
9 | 476043425804705 |
10 | 111010102122011 |
11 | 3240a135690954 |
12 | 1054a60271264b |
13 | 49c3291461a91 |
14 | 1d5acbbcd1111 |
15 | cc7962caa35b |
hex | 64f68db4161b |
111010102122011 has 2 divisors, whose sum is σ = 111010102122012. Its totient is φ = 111010102122010.
The previous prime is 111010102121929. The next prime is 111010102122019. The reversal of 111010102122011 is 110221201010111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111010102122011 - 214 = 111010102105627 is a prime.
It is a super-2 number, since 2×1110101021220112 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (111010102122019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505051061005 + 55505051061006.
It is an arithmetic number, because the mean of its divisors is an integer number (55505051061006).
Almost surely, 2111010102122011 is an apocalyptic number.
111010102122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
111010102122011 is an equidigital number, since it uses as much as digits as its factorization.
111010102122011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 111010102122011 its reverse (110221201010111), we get a palindrome (221231303132122).
The spelling of 111010102122011 in words is "one hundred eleven trillion, ten billion, one hundred two million, one hundred twenty-two thousand, eleven".
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