Base | Representation |
---|---|
bin | 1010000110001010011111… |
… | …0101000110111101100011 |
3 | 1110022020122120001211000102 |
4 | 2201202213311012331203 |
5 | 2423334332332210313 |
6 | 35335422324213015 |
7 | 2224010256252224 |
oct | 241424765067543 |
9 | 43266576054012 |
10 | 11101011210083 |
11 | 359aa04475123 |
12 | 12b354a23a16b |
13 | 626a89597252 |
14 | 2a5412a2124b |
15 | 143b6958ba58 |
hex | a18a7d46f63 |
11101011210083 has 2 divisors, whose sum is σ = 11101011210084. Its totient is φ = 11101011210082.
The previous prime is 11101011210059. The next prime is 11101011210101. The reversal of 11101011210083 is 38001211010111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11101011210083 is a prime.
It is not a weakly prime, because it can be changed into another prime (11101011215083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550505605041 + 5550505605042.
It is an arithmetic number, because the mean of its divisors is an integer number (5550505605042).
Almost surely, 211101011210083 is an apocalyptic number.
11101011210083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101011210083 is an equidigital number, since it uses as much as digits as its factorization.
11101011210083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 11101011210083 its reverse (38001211010111), we get a palindrome (49102222220194).
The spelling of 11101011210083 in words is "eleven trillion, one hundred one billion, eleven million, two hundred ten thousand, eighty-three".
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