Base | Representation |
---|---|
bin | 10000001001110111110… |
… | …101010000001011000011 |
3 | 10221010101121121010222201 |
4 | 100021313311100023003 |
5 | 121142002133322242 |
6 | 2205551201014031 |
7 | 143126416255012 |
oct | 20116765201303 |
9 | 3833347533881 |
10 | 1110112010947 |
11 | 398883320535 |
12 | 15b192324317 |
13 | 808b5a531c4 |
14 | 3ba30466a79 |
15 | 1dd235d74b7 |
hex | 10277d502c3 |
1110112010947 has 2 divisors, whose sum is σ = 1110112010948. Its totient is φ = 1110112010946.
The previous prime is 1110112010941. The next prime is 1110112010957. The reversal of 1110112010947 is 7490102110111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1110112010947 is a prime.
It is a super-3 number, since 3×11101120109473 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1110112010941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555056005473 + 555056005474.
It is an arithmetic number, because the mean of its divisors is an integer number (555056005474).
Almost surely, 21110112010947 is an apocalyptic number.
1110112010947 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110112010947 is an equidigital number, since it uses as much as digits as its factorization.
1110112010947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 28.
The spelling of 1110112010947 in words is "one trillion, one hundred ten billion, one hundred twelve million, ten thousand, nine hundred forty-seven".
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