Base | Representation |
---|---|
bin | 10000001001110111111… |
… | …001000001111001100011 |
3 | 10221010101200110110011112 |
4 | 100021313321001321203 |
5 | 121142002412013214 |
6 | 2205551234133535 |
7 | 143126430550436 |
oct | 20116771017143 |
9 | 3833350413145 |
10 | 1110113001059 |
11 | 398883937407 |
12 | 15b1927212ab |
13 | 808b600ba7a |
14 | 3ba3064381d |
15 | 1dd23730a3e |
hex | 10277e41e63 |
1110113001059 has 2 divisors, whose sum is σ = 1110113001060. Its totient is φ = 1110113001058.
The previous prime is 1110113000999. The next prime is 1110113001089. The reversal of 1110113001059 is 9501003110111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1110113001059 is a prime.
It is not a weakly prime, because it can be changed into another prime (1110113001089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555056500529 + 555056500530.
It is an arithmetic number, because the mean of its divisors is an integer number (555056500530).
Almost surely, 21110113001059 is an apocalyptic number.
1110113001059 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110113001059 is an equidigital number, since it uses as much as digits as its factorization.
1110113001059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135, while the sum is 23.
The spelling of 1110113001059 in words is "one trillion, one hundred ten billion, one hundred thirteen million, one thousand, fifty-nine".
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