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111011313311147 is a prime number
BaseRepresentation
bin11001001111011011010101…
…111001010101110110101011
3112120001120121021221221221002
4121033123111321111312223
5104022302132201424042
61032033520541505215
732245205555031164
oct3117332571256653
9476046537857832
10111011313311147
113240a6a733a207
121054a8a027220b
1349c3425373142
141d5ad94ad476b
15cc79d42a6132
hex64f6d5e55dab

111011313311147 has 2 divisors, whose sum is σ = 111011313311148. Its totient is φ = 111011313311146.

The previous prime is 111011313311083. The next prime is 111011313311159. The reversal of 111011313311147 is 741113313110111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111011313311147 - 26 = 111011313311083 is a prime.

It is not a weakly prime, because it can be changed into another prime (111011313311347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505656655573 + 55505656655574.

It is an arithmetic number, because the mean of its divisors is an integer number (55505656655574).

Almost surely, 2111011313311147 is an apocalyptic number.

111011313311147 is a deficient number, since it is larger than the sum of its proper divisors (1).

111011313311147 is an equidigital number, since it uses as much as digits as its factorization.

111011313311147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 29.

Adding to 111011313311147 its reverse (741113313110111), we get a palindrome (852124626421258).

The spelling of 111011313311147 in words is "one hundred eleven trillion, eleven billion, three hundred thirteen million, three hundred eleven thousand, one hundred forty-seven".