Base | Representation |
---|---|
bin | 11001001111011011111110… |
… | …111100100011111011011011 |
3 | 112120001122101021220001100111 |
4 | 121033123332330203323123 |
5 | 104022310040004133313 |
6 | 1032034113143145151 |
7 | 32245231620000652 |
oct | 3117337674437333 |
9 | 476048337801314 |
10 | 111012002021083 |
11 | 3240aa20078179 |
12 | 1054aa52a451b7 |
13 | 49c3504c5b707 |
14 | 1d5b01c370199 |
15 | cc7a2499843d |
hex | 64f6fef23edb |
111012002021083 has 2 divisors, whose sum is σ = 111012002021084. Its totient is φ = 111012002021082.
The previous prime is 111012002021009. The next prime is 111012002021143. The reversal of 111012002021083 is 380120200210111.
It is a strong prime.
It is an emirp because it is prime and its reverse (380120200210111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111012002021083 - 217 = 111012001890011 is a prime.
It is not a weakly prime, because it can be changed into another prime (111012002021383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55506001010541 + 55506001010542.
It is an arithmetic number, because the mean of its divisors is an integer number (55506001010542).
Almost surely, 2111012002021083 is an apocalyptic number.
111012002021083 is a deficient number, since it is larger than the sum of its proper divisors (1).
111012002021083 is an equidigital number, since it uses as much as digits as its factorization.
111012002021083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 111012002021083 its reverse (380120200210111), we get a palindrome (491132202231194).
The spelling of 111012002021083 in words is "one hundred eleven trillion, twelve billion, two million, twenty-one thousand, eighty-three".
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