Base | Representation |
---|---|
bin | 11001001111011100000100… |
… | …110010101101100010100011 |
3 | 112120001122122010110002111102 |
4 | 121033130010302231202203 |
5 | 104022310240111233212 |
6 | 1032034131005305015 |
7 | 32245234220452025 |
oct | 3117340462554243 |
9 | 476048563402442 |
10 | 111012100102307 |
11 | 3240aa70479038 |
12 | 1054aa7b86516b |
13 | 49c351c37ca41 |
14 | 1d5b02b3c2015 |
15 | cc7a2d3be5c2 |
hex | 64f704cad8a3 |
111012100102307 has 2 divisors, whose sum is σ = 111012100102308. Its totient is φ = 111012100102306.
The previous prime is 111012100102187. The next prime is 111012100102313. The reversal of 111012100102307 is 703201001210111.
It is a strong prime.
It is an emirp because it is prime and its reverse (703201001210111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111012100102307 - 210 = 111012100101283 is a prime.
It is not a weakly prime, because it can be changed into another prime (111012100162307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55506050051153 + 55506050051154.
It is an arithmetic number, because the mean of its divisors is an integer number (55506050051154).
Almost surely, 2111012100102307 is an apocalyptic number.
111012100102307 is a deficient number, since it is larger than the sum of its proper divisors (1).
111012100102307 is an equidigital number, since it uses as much as digits as its factorization.
111012100102307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 111012100102307 its reverse (703201001210111), we get a palindrome (814213101312418).
The spelling of 111012100102307 in words is "one hundred eleven trillion, twelve billion, one hundred million, one hundred two thousand, three hundred seven".
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