Base | Representation |
---|---|
bin | 1010000110001011001110… |
… | …1011100000100101000011 |
3 | 1110022021011102011102011201 |
4 | 2201202303223200211003 |
5 | 2423340234231121123 |
6 | 35335454145322031 |
7 | 2224015222152364 |
oct | 241426353404503 |
9 | 43267142142151 |
10 | 11101210020163 |
11 | 359aaa671507a |
12 | 12b35a4936317 |
13 | 626abb825a53 |
14 | 2a54311b3b6b |
15 | 143b7bc5d5ad |
hex | a18b3ae0943 |
11101210020163 has 2 divisors, whose sum is σ = 11101210020164. Its totient is φ = 11101210020162.
The previous prime is 11101210020119. The next prime is 11101210020211. The reversal of 11101210020163 is 36102001210111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11101210020163 - 221 = 11101207923011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11101210020163.
It is not a weakly prime, because it can be changed into another prime (11101210050163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550605010081 + 5550605010082.
It is an arithmetic number, because the mean of its divisors is an integer number (5550605010082).
Almost surely, 211101210020163 is an apocalyptic number.
11101210020163 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101210020163 is an equidigital number, since it uses as much as digits as its factorization.
11101210020163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 11101210020163 its reverse (36102001210111), we get a palindrome (47203211230274).
The spelling of 11101210020163 in words is "eleven trillion, one hundred one billion, two hundred ten million, twenty thousand, one hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •