Base | Representation |
---|---|
bin | 11001001111011100000101… |
… | …100000100100000010011011 |
3 | 112120001122122222001202102122 |
4 | 121033130011200210002123 |
5 | 104022310301200401021 |
6 | 1032034132115051455 |
7 | 32245234424562632 |
oct | 3117340540440233 |
9 | 476048588052378 |
10 | 111012112122011 |
11 | 3240aa77238681 |
12 | 1054aa838a0b8b |
13 | 49c35219ca9a9 |
14 | 1d5b02cc30519 |
15 | cc7a2e495bab |
hex | 64f70582409b |
111012112122011 has 2 divisors, whose sum is σ = 111012112122012. Its totient is φ = 111012112122010.
The previous prime is 111012112121941. The next prime is 111012112122031. The reversal of 111012112122011 is 110221211210111.
It is a strong prime.
It is an emirp because it is prime and its reverse (110221211210111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111012112122011 is a prime.
It is not a weakly prime, because it can be changed into another prime (111012112122031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55506056061005 + 55506056061006.
It is an arithmetic number, because the mean of its divisors is an integer number (55506056061006).
Almost surely, 2111012112122011 is an apocalyptic number.
111012112122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
111012112122011 is an equidigital number, since it uses as much as digits as its factorization.
111012112122011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 17.
Adding to 111012112122011 its reverse (110221211210111), we get a palindrome (221233323332122).
The spelling of 111012112122011 in words is "one hundred eleven trillion, twelve billion, one hundred twelve million, one hundred twenty-two thousand, eleven".
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