Base | Representation |
---|---|
bin | 10100101011010111… |
… | …10001001010000001 |
3 | 1001122122220001210122 |
4 | 22111223301022001 |
5 | 140213402311223 |
6 | 5033321310025 |
7 | 542045520251 |
oct | 122553611201 |
9 | 31578801718 |
10 | 11101213313 |
11 | 4787388963 |
12 | 2199935315 |
13 | 107bba4498 |
14 | 7744d9961 |
15 | 44e8d35c8 |
hex | 295af1281 |
11101213313 has 2 divisors, whose sum is σ = 11101213314. Its totient is φ = 11101213312.
The previous prime is 11101213297. The next prime is 11101213433. The reversal of 11101213313 is 31331210111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6950890384 + 4150322929 = 83372^2 + 64423^2 .
It is an emirp because it is prime and its reverse (31331210111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11101213313 - 24 = 11101213297 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11101213291 and 11101213300.
It is not a weakly prime, because it can be changed into another prime (11101213913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550606656 + 5550606657.
It is an arithmetic number, because the mean of its divisors is an integer number (5550606657).
Almost surely, 211101213313 is an apocalyptic number.
It is an amenable number.
11101213313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101213313 is an equidigital number, since it uses as much as digits as its factorization.
11101213313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11101213313 its reverse (31331210111), we get a palindrome (42432423424).
The spelling of 11101213313 in words is "eleven billion, one hundred one million, two hundred thirteen thousand, three hundred thirteen".
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