Base | Representation |
---|---|
bin | 10000001001111000011… |
… | …011110000001000100011 |
3 | 10221010102022120220010201 |
4 | 100021320123300020203 |
5 | 121142012224301311 |
6 | 2205552201210031 |
7 | 143126601120613 |
oct | 20117033601043 |
9 | 3833368526121 |
10 | 1110122103331 |
11 | 398888a9404a |
12 | 15b195790917 |
13 | 808b7b77b27 |
14 | 3ba31932a43 |
15 | 1dd2442c9c1 |
hex | 102786f0223 |
1110122103331 has 2 divisors, whose sum is σ = 1110122103332. Its totient is φ = 1110122103330.
The previous prime is 1110122103229. The next prime is 1110122103449. The reversal of 1110122103331 is 1333012210111.
It is a weak prime.
It is an emirp because it is prime and its reverse (1333012210111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1110122103331 - 213 = 1110122095139 is a prime.
It is a super-2 number, since 2×11101221033312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1110122103299 and 1110122103308.
It is not a weakly prime, because it can be changed into another prime (1110122103031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555061051665 + 555061051666.
It is an arithmetic number, because the mean of its divisors is an integer number (555061051666).
Almost surely, 21110122103331 is an apocalyptic number.
1110122103331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110122103331 is an equidigital number, since it uses as much as digits as its factorization.
1110122103331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1110122103331 its reverse (1333012210111), we get a palindrome (2443134313442).
The spelling of 1110122103331 in words is "one trillion, one hundred ten billion, one hundred twenty-two million, one hundred three thousand, three hundred thirty-one".
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