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11101222000113 = 374312293712071
BaseRepresentation
bin1010000110001011010001…
…1001001101010111110001
31110022021012020201001120120
42201202310121031113301
52423340300313000423
635335455254200453
72224015426036350
oct241426431152761
943267166631516
1011101222000113
1135a0002457863
1212b35a8953129
13626ac115b88b
142a5432a11997
15143b7cd27ee3
hexa18b464d5f1

11101222000113 has 16 divisors (see below), whose sum is σ = 17309546597376. Its totient is φ = 6196030883280.

The previous prime is 11101222000087. The next prime is 11101222000117. The reversal of 11101222000113 is 31100022210111.

It is not a de Polignac number, because 11101222000113 - 25 = 11101222000081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11101222000092 and 11101222000101.

It is not an unprimeable number, because it can be changed into a prime (11101222000117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6146855133 + ... + 6146856938.

It is an arithmetic number, because the mean of its divisors is an integer number (1081846662336).

Almost surely, 211101222000113 is an apocalyptic number.

It is an amenable number.

11101222000113 is a deficient number, since it is larger than the sum of its proper divisors (6208324597263).

11101222000113 is a wasteful number, since it uses less digits than its factorization.

11101222000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12293712124.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11101222000113 its reverse (31100022210111), we get a palindrome (42201244210224).

The spelling of 11101222000113 in words is "eleven trillion, one hundred one billion, two hundred twenty-two million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 7 21 43 129 301 903 12293712071 36881136213 86055984497 258167953491 528629619053 1585888857159 3700407333371 11101222000113