Base | Representation |
---|---|
bin | 10000001001111000011… |
… | …111101011001000001001 |
3 | 10221010102101112010101101 |
4 | 100021320133223020021 |
5 | 121142013010201101 |
6 | 2205552235221401 |
7 | 143126612632114 |
oct | 20117037531011 |
9 | 3833371463341 |
10 | 1110123131401 |
11 | 398889626499 |
12 | 15b195ba7861 |
13 | 808b8147a5b |
14 | 3ba31b1d57b |
15 | 1dd24582401 |
hex | 102787eb209 |
1110123131401 has 2 divisors, whose sum is σ = 1110123131402. Its totient is φ = 1110123131400.
The previous prime is 1110123131393. The next prime is 1110123131419. The reversal of 1110123131401 is 1041313210111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 744382426176 + 365740705225 = 862776^2 + 604765^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110123131401 - 23 = 1110123131393 is a prime.
It is not a weakly prime, because it can be changed into another prime (1510123131401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555061565700 + 555061565701.
It is an arithmetic number, because the mean of its divisors is an integer number (555061565701).
Almost surely, 21110123131401 is an apocalyptic number.
It is an amenable number.
1110123131401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110123131401 is an equidigital number, since it uses as much as digits as its factorization.
1110123131401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1110123131401 its reverse (1041313210111), we get a palindrome (2151436341512).
The spelling of 1110123131401 in words is "one trillion, one hundred ten billion, one hundred twenty-three million, one hundred thirty-one thousand, four hundred one".
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