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1110123221131 is a prime number
BaseRepresentation
bin10000001001111000100…
…000000001000010001011
310221010102101200200110201
4100021320200001002023
5121142013021034011
62205552241153031
7143126613454531
oct20117040010213
93833371620421
101110123221131
11398889687951
1215b19602b777
13808b8179852
143ba31b44151
151dd2459dcc1
hex1027880108b

1110123221131 has 2 divisors, whose sum is σ = 1110123221132. Its totient is φ = 1110123221130.

The previous prime is 1110123221083. The next prime is 1110123221209. The reversal of 1110123221131 is 1311223210111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1110123221131 - 223 = 1110114832523 is a prime.

It is a super-2 number, since 2×11101232211312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1110123221099 and 1110123221108.

It is not a weakly prime, because it can be changed into another prime (1110123221231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555061610565 + 555061610566.

It is an arithmetic number, because the mean of its divisors is an integer number (555061610566).

Almost surely, 21110123221131 is an apocalyptic number.

1110123221131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110123221131 is an equidigital number, since it uses as much as digits as its factorization.

1110123221131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1110123221131 its reverse (1311223210111), we get a palindrome (2421346431242).

The spelling of 1110123221131 in words is "one trillion, one hundred ten billion, one hundred twenty-three million, two hundred twenty-one thousand, one hundred thirty-one".