Base | Representation |
---|---|
bin | 10000001001111000100… |
… | …000000001000010001011 |
3 | 10221010102101200200110201 |
4 | 100021320200001002023 |
5 | 121142013021034011 |
6 | 2205552241153031 |
7 | 143126613454531 |
oct | 20117040010213 |
9 | 3833371620421 |
10 | 1110123221131 |
11 | 398889687951 |
12 | 15b19602b777 |
13 | 808b8179852 |
14 | 3ba31b44151 |
15 | 1dd2459dcc1 |
hex | 1027880108b |
1110123221131 has 2 divisors, whose sum is σ = 1110123221132. Its totient is φ = 1110123221130.
The previous prime is 1110123221083. The next prime is 1110123221209. The reversal of 1110123221131 is 1311223210111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110123221131 - 223 = 1110114832523 is a prime.
It is a super-2 number, since 2×11101232211312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1110123221099 and 1110123221108.
It is not a weakly prime, because it can be changed into another prime (1110123221231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555061610565 + 555061610566.
It is an arithmetic number, because the mean of its divisors is an integer number (555061610566).
Almost surely, 21110123221131 is an apocalyptic number.
1110123221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110123221131 is an equidigital number, since it uses as much as digits as its factorization.
1110123221131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1110123221131 its reverse (1311223210111), we get a palindrome (2421346431242).
The spelling of 1110123221131 in words is "one trillion, one hundred ten billion, one hundred twenty-three million, two hundred twenty-one thousand, one hundred thirty-one".
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