Base | Representation |
---|---|
bin | 1010000110001011101011… |
… | …1001011001010101111011 |
3 | 1110022021110211222221221001 |
4 | 2201202322321121111323 |
5 | 2423341011230213201 |
6 | 35335514152425431 |
7 | 2224021222265032 |
oct | 241427271312573 |
9 | 43267424887831 |
10 | 11101331101051 |
11 | 35a0058aa4a24 |
12 | 12b36193a8277 |
13 | 626b0a93a949 |
14 | 2a54432d1719 |
15 | 143b876c9301 |
hex | a18bae5957b |
11101331101051 has 2 divisors, whose sum is σ = 11101331101052. Its totient is φ = 11101331101050.
The previous prime is 11101331101039. The next prime is 11101331101067. The reversal of 11101331101051 is 15010113310111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11101331101051 - 239 = 10551575287163 is a prime.
It is not a weakly prime, because it can be changed into another prime (11101331101351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550665550525 + 5550665550526.
It is an arithmetic number, because the mean of its divisors is an integer number (5550665550526).
Almost surely, 211101331101051 is an apocalyptic number.
11101331101051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11101331101051 is an equidigital number, since it uses as much as digits as its factorization.
11101331101051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 19.
Adding to 11101331101051 its reverse (15010113310111), we get a palindrome (26111444411162).
The spelling of 11101331101051 in words is "eleven trillion, one hundred one billion, three hundred thirty-one million, one hundred one thousand, fifty-one".
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