Base | Representation |
---|---|
bin | 11001001111100011100111… |
… | …100110001011011000101011 |
3 | 112120002102112122020022002112 |
4 | 121033203213212023120223 |
5 | 104022423332223241021 |
6 | 1032041550442552535 |
7 | 32245642025322146 |
oct | 3117434746133053 |
9 | 476072478208075 |
10 | 111020200212011 |
11 | 32413447802382 |
12 | 1055056050874b |
13 | 49c421057456c |
14 | 1d5b5990a905d |
15 | cc7d54591d5b |
hex | 64f8e798b62b |
111020200212011 has 2 divisors, whose sum is σ = 111020200212012. Its totient is φ = 111020200212010.
The previous prime is 111020200211959. The next prime is 111020200212083. The reversal of 111020200212011 is 110212002020111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111020200212011 - 238 = 110745322305067 is a prime.
It is a super-3 number, since 3×1110202002120113 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (111020200212091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510100106005 + 55510100106006.
It is an arithmetic number, because the mean of its divisors is an integer number (55510100106006).
Almost surely, 2111020200212011 is an apocalyptic number.
111020200212011 is a deficient number, since it is larger than the sum of its proper divisors (1).
111020200212011 is an equidigital number, since it uses as much as digits as its factorization.
111020200212011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 111020200212011 its reverse (110212002020111), we get a palindrome (221232202232122).
The spelling of 111020200212011 in words is "one hundred eleven trillion, twenty billion, two hundred million, two hundred twelve thousand, eleven".
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