Base | Representation |
---|---|
bin | 110011101100101010… |
… | …0100100011001000100 |
3 | 101121120012011001010020 |
4 | 1213121110210121010 |
5 | 3304332134331322 |
6 | 123000232455140 |
7 | 11010120246363 |
oct | 1473124443104 |
9 | 347505131106 |
10 | 111020230212 |
11 | 430a1031181 |
12 | 1962454a4b0 |
13 | a61399b218 |
14 | 55328b97da |
15 | 2d4b97305c |
hex | 19d9524644 |
111020230212 has 12 divisors (see below), whose sum is σ = 259047203856. Its totient is φ = 37006743400.
The previous prime is 111020230199. The next prime is 111020230249. The reversal of 111020230212 is 212032020111.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 111020230191 and 111020230200.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4625842914 + ... + 4625842937.
It is an arithmetic number, because the mean of its divisors is an integer number (21587266988).
Almost surely, 2111020230212 is an apocalyptic number.
111020230212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
111020230212 is an abundant number, since it is smaller than the sum of its proper divisors (148026973644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111020230212 is a wasteful number, since it uses less digits than its factorization.
111020230212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9251685858 (or 9251685856 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 111020230212 its reverse (212032020111), we get a palindrome (323052250323).
The spelling of 111020230212 in words is "one hundred eleven billion, twenty million, two hundred thirty thousand, two hundred twelve".
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