Search a number
-
+
11102066993273 is a prime number
BaseRepresentation
bin1010000110001110011011…
…0000100110100001111001
31110022100101010201011021112
42201203212300212201321
52423344013122241043
635340115201250105
72224045366255304
oct241434660464171
943270333634245
1011102066993273
1135a03a6429713
1212b37a3933935
13626bc7235c29
142a54b2d2db3b
15143bcc0db518
hexa18e6c26879

11102066993273 has 2 divisors, whose sum is σ = 11102066993274. Its totient is φ = 11102066993272.

The previous prime is 11102066993249. The next prime is 11102066993291. The reversal of 11102066993273 is 37239966020111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11000810662009 + 101256331264 = 3316747^2 + 318208^2 .

It is an emirp because it is prime and its reverse (37239966020111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11102066993273 - 216 = 11102066927737 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11102066993293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551033496636 + 5551033496637.

It is an arithmetic number, because the mean of its divisors is an integer number (5551033496637).

Almost surely, 211102066993273 is an apocalyptic number.

It is an amenable number.

11102066993273 is a deficient number, since it is larger than the sum of its proper divisors (1).

11102066993273 is an equidigital number, since it uses as much as digits as its factorization.

11102066993273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 734832, while the sum is 50.

The spelling of 11102066993273 in words is "eleven trillion, one hundred two billion, sixty-six million, nine hundred ninety-three thousand, two hundred seventy-three".