Base | Representation |
---|---|
bin | 110011101100101011… |
… | …1100000000100111001 |
3 | 101121120020121002122201 |
4 | 1213121113200010321 |
5 | 3304332333431334 |
6 | 123000301150201 |
7 | 11010126630556 |
oct | 1473127400471 |
9 | 347506532581 |
10 | 111020998969 |
11 | 430a1506811 |
12 | 1962485b361 |
13 | a613baa0ca |
14 | 5532a39a2d |
15 | 2d4ba75c14 |
hex | 19d95e0139 |
111020998969 has 2 divisors, whose sum is σ = 111020998970. Its totient is φ = 111020998968.
The previous prime is 111020998931. The next prime is 111020999003. The reversal of 111020998969 is 969899020111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78015193344 + 33005805625 = 279312^2 + 181675^2 .
It is a cyclic number.
It is not a de Polignac number, because 111020998969 - 27 = 111020998841 is a prime.
It is a super-2 number, since 2×1110209989692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111020998909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510499484 + 55510499485.
It is an arithmetic number, because the mean of its divisors is an integer number (55510499485).
Almost surely, 2111020998969 is an apocalyptic number.
It is an amenable number.
111020998969 is a deficient number, since it is larger than the sum of its proper divisors (1).
111020998969 is an equidigital number, since it uses as much as digits as its factorization.
111020998969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 55.
The spelling of 111020998969 in words is "one hundred eleven billion, twenty million, nine hundred ninety-eight thousand, nine hundred sixty-nine".
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