Base | Representation |
---|---|
bin | 11001001111100100011101… |
… | …001111000001100001111001 |
3 | 112120002111212100112221210111 |
4 | 121033210131033001201321 |
5 | 104022432203112040433 |
6 | 1032042220030544321 |
7 | 32246003233333231 |
oct | 3117443517014171 |
9 | 476074770487714 |
10 | 111021100111993 |
11 | 32413869776575 |
12 | 105507719680a1 |
13 | 49c4324b34566 |
14 | 1d5b6427dacc1 |
15 | cc7da859ddcd |
hex | 64f91d3c1879 |
111021100111993 has 2 divisors, whose sum is σ = 111021100111994. Its totient is φ = 111021100111992.
The previous prime is 111021100111979. The next prime is 111021100112033. The reversal of 111021100111993 is 399111001120111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86352266078464 + 24668834033529 = 9292592^2 + 4966773^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111021100111993 is a prime.
It is not a weakly prime, because it can be changed into another prime (111021100111913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510550055996 + 55510550055997.
It is an arithmetic number, because the mean of its divisors is an integer number (55510550055997).
Almost surely, 2111021100111993 is an apocalyptic number.
It is an amenable number.
111021100111993 is a deficient number, since it is larger than the sum of its proper divisors (1).
111021100111993 is an equidigital number, since it uses as much as digits as its factorization.
111021100111993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 31.
The spelling of 111021100111993 in words is "one hundred eleven trillion, twenty-one billion, one hundred million, one hundred eleven thousand, nine hundred ninety-three".
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