Base | Representation |
---|---|
bin | 10000001001111101110… |
… | …011011111001001111011 |
3 | 10221010122121010212001202 |
4 | 100021331303133021323 |
5 | 121142203311230243 |
6 | 2210005140404415 |
7 | 143132044043255 |
oct | 20117563371173 |
9 | 3833577125052 |
10 | 1110212211323 |
11 | 398924939566 |
12 | 15b1bb9a670b |
13 | 80900736c77 |
14 | 3ba3d8aacd5 |
15 | 1dd2c2cb4b8 |
hex | 1027dcdf27b |
1110212211323 has 2 divisors, whose sum is σ = 1110212211324. Its totient is φ = 1110212211322.
The previous prime is 1110212211319. The next prime is 1110212211347. The reversal of 1110212211323 is 3231122120111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110212211323 - 22 = 1110212211319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1110212211295 and 1110212211304.
It is not a weakly prime, because it can be changed into another prime (1110212211023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555106105661 + 555106105662.
It is an arithmetic number, because the mean of its divisors is an integer number (555106105662).
Almost surely, 21110212211323 is an apocalyptic number.
1110212211323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110212211323 is an equidigital number, since it uses as much as digits as its factorization.
1110212211323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1110212211323 its reverse (3231122120111), we get a palindrome (4341334331434).
The spelling of 1110212211323 in words is "one trillion, one hundred ten billion, two hundred twelve million, two hundred eleven thousand, three hundred twenty-three".
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