Base | Representation |
---|---|
bin | 110011101100101100… |
… | …1000110111000001011 |
3 | 101121120021101111021001 |
4 | 1213121121012320023 |
5 | 3304332440420133 |
6 | 123000314155431 |
7 | 11010133333312 |
oct | 1473131067013 |
9 | 347507344231 |
10 | 111021420043 |
11 | 430a1774106 |
12 | 19624a22b77 |
13 | a613cc6971 |
14 | 5532b09279 |
15 | 2d4bb0a87d |
hex | 19d9646e0b |
111021420043 has 2 divisors, whose sum is σ = 111021420044. Its totient is φ = 111021420042.
The previous prime is 111021420023. The next prime is 111021420047. The reversal of 111021420043 is 340024120111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111021420043 - 25 = 111021420011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111021420043.
It is not a weakly prime, because it can be changed into another prime (111021420047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510710021 + 55510710022.
It is an arithmetic number, because the mean of its divisors is an integer number (55510710022).
Almost surely, 2111021420043 is an apocalyptic number.
111021420043 is a deficient number, since it is larger than the sum of its proper divisors (1).
111021420043 is an equidigital number, since it uses as much as digits as its factorization.
111021420043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 111021420043 its reverse (340024120111), we get a palindrome (451045540154).
The spelling of 111021420043 in words is "one hundred eleven billion, twenty-one million, four hundred twenty thousand, forty-three".
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