111022004131 has 2 divisors, whose sum is σ = 111022004132. Its totient is φ = 111022004130.

The previous prime is 111022004113. The next prime is 111022004207. The reversal of 111022004131 is 131400220111.

Together with previous prime (111022004113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (131400220111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111022004131 - 2¹¹ = 111022002083 is a prime.

It is a super-3 number, since 3×111022004131³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (111022304131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55511002065 + 55511002066.

It is an arithmetic number, because the mean of its divisors is an integer number (55511002066).

Almost surely, 2^111022004131 is an apocalyptic number.

111022004131 is a deficient number, since it is larger than the sum of its proper divisors (1).

111022004131 is an equidigital number, since it uses as much as digits as its factorization.

111022004131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 111022004131 its reverse (131400220111), we get a palindrome (242422224242).

The spelling of 111022004131 in words is "one hundred eleven billion, twenty-two million, four thousand, one hundred thirty-one".