Base | Representation |
---|---|
bin | 11001001111100101010011… |
… | …100010001111100110010100 |
3 | 112120002121012211202221212112 |
4 | 121033211103202033212110 |
5 | 104022441034321320040 |
6 | 1032042450253010152 |
7 | 32246034634640300 |
oct | 3117452342174624 |
9 | 476077184687775 |
10 | 111022011120020 |
11 | 32414196a37370 |
12 | 10550986a83958 |
13 | 49c443b7b3570 |
14 | 1d5b6cb7c0d00 |
15 | cc7e0d552365 |
hex | 64f95388f994 |
111022011120020 has 1152 divisors, whose sum is σ = 344713936896000. Its totient is φ = 29437948108800.
The previous prime is 111022011119917. The next prime is 111022011120047. The reversal of 111022011120020 is 20021110220111.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is a junction number, because it is equal to n+sod(n) for n = 111022011119977 and 111022011120004.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 23880834656 + ... + 23880839304.
It is an arithmetic number, because the mean of its divisors is an integer number (299230848000).
Almost surely, 2111022011120020 is an apocalyptic number.
111022011120020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111022011120020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (172356968448000).
111022011120020 is an abundant number, since it is smaller than the sum of its proper divisors (233691925775980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111022011120020 is a wasteful number, since it uses less digits than its factorization.
111022011120020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4989 (or 4980 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 111022011120020 its reverse (20021110220111), we get a palindrome (131043121340131).
It can be divided in two parts, 11102201 and 1120020, that added together give a palindrome (12222221).
The spelling of 111022011120020 in words is "one hundred eleven trillion, twenty-two billion, eleven million, one hundred twenty thousand, twenty".
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