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11102212113 = 347109722377
BaseRepresentation
bin10100101011011111…
…00101000000010001
31001122201202210220020
422111233211000101
5140214131241423
65033354534053
7542060150226
oct122557450021
931581683806
1011102212113
114787a00313
12219a137329
13107c163ca5
147746b994d
1544ea2e4e3
hex295be5011

11102212113 has 16 divisors (see below), whose sum is σ = 15256623360. Its totient is φ = 7177527936.

The previous prime is 11102212061. The next prime is 11102212181. The reversal of 11102212113 is 31121220111.

It is a de Polignac number, because none of the positive numbers 2k-11102212113 is a prime.

It is a super-2 number, since 2×111022121132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11102212092 and 11102212101.

It is not an unprimeable number, because it can be changed into a prime (11102212313) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 345820 + ... + 376557.

It is an arithmetic number, because the mean of its divisors is an integer number (953538960).

Almost surely, 211102212113 is an apocalyptic number.

It is an amenable number.

11102212113 is a deficient number, since it is larger than the sum of its proper divisors (4154411247).

11102212113 is a wasteful number, since it uses less digits than its factorization.

11102212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 722536.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11102212113 its reverse (31121220111), we get a palindrome (42223432224).

The spelling of 11102212113 in words is "eleven billion, one hundred two million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 47 109 141 327 5123 15369 722377 2167131 33951719 78739093 101855157 236217279 3700737371 11102212113