Base | Representation |
---|---|
bin | 1010000110001111010101… |
… | …0111001111011011111011 |
3 | 1110022101000012201221212211 |
4 | 2201203311113033123323 |
5 | 2423400013333101243 |
6 | 35340155352515551 |
7 | 2224054432645312 |
oct | 241436527173373 |
9 | 43271005657784 |
10 | 11102312003323 |
11 | 35a0511764362 |
12 | 12b38519abbb7 |
13 | 626c35c1c2a8 |
14 | 2a54d76ab279 |
15 | 143be3886d9d |
hex | a18f55cf6fb |
11102312003323 has 2 divisors, whose sum is σ = 11102312003324. Its totient is φ = 11102312003322.
The previous prime is 11102312003309. The next prime is 11102312003333. The reversal of 11102312003323 is 32330021320111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11102312003323 is a prime.
It is a super-2 number, since 2×111023120033232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11102312003294 and 11102312003303.
It is not a weakly prime, because it can be changed into another prime (11102312003333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551156001661 + 5551156001662.
It is an arithmetic number, because the mean of its divisors is an integer number (5551156001662).
Almost surely, 211102312003323 is an apocalyptic number.
11102312003323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102312003323 is an equidigital number, since it uses as much as digits as its factorization.
11102312003323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11102312003323 its reverse (32330021320111), we get a palindrome (43432333323434).
The spelling of 11102312003323 in words is "eleven trillion, one hundred two billion, three hundred twelve million, three thousand, three hundred twenty-three".
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