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11103000133 = 41926498807
BaseRepresentation
bin10100101011100101…
…00101011001000101
31001122210020211212011
422111302211121011
5140214332001013
65033423454221
7542066641531
oct122562453105
931583224764
1011103000133
114788399375
12219a457371
13107c37b884
14774842bc1
1544eb37c3d
hex295ca5645

11103000133 has 4 divisors (see below), whose sum is σ = 11129499360. Its totient is φ = 11076500908.

The previous prime is 11103000119. The next prime is 11103000163. The reversal of 11103000133 is 33100030111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11103000133 is a prime.

It is a super-2 number, since 2×111030001332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11103000163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13248985 + ... + 13249822.

It is an arithmetic number, because the mean of its divisors is an integer number (2782374840).

Almost surely, 211103000133 is an apocalyptic number.

It is an amenable number.

11103000133 is a deficient number, since it is larger than the sum of its proper divisors (26499227).

11103000133 is an equidigital number, since it uses as much as digits as its factorization.

11103000133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26499226.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 11103000133 its reverse (33100030111), we get a palindrome (44203030244).

The spelling of 11103000133 in words is "eleven billion, one hundred three million, one hundred thirty-three", and thus it is an aban number.

Divisors: 1 419 26498807 11103000133