11103124344083 has 2 divisors, whose sum is σ = 11103124344084. Its totient is φ = 11103124344082.

The previous prime is 11103124344041. The next prime is 11103124344119. The reversal of 11103124344083 is 38044342130111.

It is a strong prime.

It is an emirp because it is prime and its reverse (38044342130111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11103124344083 - 2¹⁴ = 11103124327699 is a prime.

It is a super-2 number, since 2×11103124344083² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11103124344023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551562172041 + 5551562172042.

It is an arithmetic number, because the mean of its divisors is an integer number (5551562172042).

Almost surely, 2^{11103124344083} is an apocalyptic number.

11103124344083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11103124344083 is an equidigital number, since it uses as much as digits as its factorization.

11103124344083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 35.

Adding to 11103124344083 its reverse (38044342130111), we get a palindrome (49147466474194).

The spelling of 11103124344083 in words is "eleven trillion, one hundred three billion, one hundred twenty-four million, three hundred forty-four thousand, eighty-three".