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111032303021209 is a prime number
BaseRepresentation
bin11001001111101110111000…
…111110101110110010011001
3112120010120210002210201011001
4121033232320332232302121
5104023123124033134314
61032051311424105001
732246550655441153
oct3117567076566231
9476116702721131
10111032303021209
11324185984a4029
1210552979765161
1349c53bbac441b
141d5bdc6609ad3
15cc8311d6e674
hex64fbb8faec99

111032303021209 has 2 divisors, whose sum is σ = 111032303021210. Its totient is φ = 111032303021208.

The previous prime is 111032303021117. The next prime is 111032303021279. The reversal of 111032303021209 is 902120303230111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105806836200025 + 5225466821184 = 10286245^2 + 2285928^2 .

It is a cyclic number.

It is not a de Polignac number, because 111032303021209 - 225 = 111032269466777 is a prime.

It is a super-4 number, since 4×1110323030212094 (a number of 57 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (111032303021279) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55516151510604 + 55516151510605.

It is an arithmetic number, because the mean of its divisors is an integer number (55516151510605).

Almost surely, 2111032303021209 is an apocalyptic number.

It is an amenable number.

111032303021209 is a deficient number, since it is larger than the sum of its proper divisors (1).

111032303021209 is an equidigital number, since it uses as much as digits as its factorization.

111032303021209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 28.

The spelling of 111032303021209 in words is "one hundred eleven trillion, thirty-two billion, three hundred three million, twenty-one thousand, two hundred nine".