111034345364843 has 2 divisors, whose sum is σ = 111034345364844. Its totient is φ = 111034345364842.

The previous prime is 111034345364821. The next prime is 111034345364863. The reversal of 111034345364843 is 348463543430111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111034345364843 - 2²⁰ = 111034344316267 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111034345364791 and 111034345364800.

It is not a weakly prime, because it can be changed into another prime (111034345364863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55517172682421 + 55517172682422.

It is an arithmetic number, because the mean of its divisors is an integer number (55517172682422).

Almost surely, 2^{111034345364843} is an apocalyptic number.

111034345364843 is a deficient number, since it is larger than the sum of its proper divisors (1).

111034345364843 is an equidigital number, since it uses as much as digits as its factorization.

111034345364843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4976640, while the sum is 50.

Adding to 111034345364843 its reverse (348463543430111), we get a palindrome (459497888794954).

The spelling of 111034345364843 in words is "one hundred eleven trillion, thirty-four billion, three hundred forty-five million, three hundred sixty-four thousand, eight hundred forty-three".