Base | Representation |
---|---|
bin | 110011101101000110… |
… | …1101100010110110001 |
3 | 101121121020022211201112 |
4 | 1213122031230112301 |
5 | 3304400003030131 |
6 | 123001525443105 |
7 | 11010361445645 |
oct | 1473215542661 |
9 | 347536284645 |
10 | 111035205041 |
11 | 430a9529a72 |
12 | 19629570495 |
13 | a616b12277 |
14 | 5534896c25 |
15 | 2d4ce3002b |
hex | 19da36c5b1 |
111035205041 has 2 divisors, whose sum is σ = 111035205042. Its totient is φ = 111035205040.
The previous prime is 111035204963. The next prime is 111035205077. The reversal of 111035205041 is 140502530111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73181611441 + 37853593600 = 270521^2 + 194560^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111035205041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111035204998 and 111035205016.
It is not a weakly prime, because it can be changed into another prime (111035255041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55517602520 + 55517602521.
It is an arithmetic number, because the mean of its divisors is an integer number (55517602521).
Almost surely, 2111035205041 is an apocalyptic number.
It is an amenable number.
111035205041 is a deficient number, since it is larger than the sum of its proper divisors (1).
111035205041 is an equidigital number, since it uses as much as digits as its factorization.
111035205041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 111035205041 its reverse (140502530111), we get a palindrome (251537735152).
The spelling of 111035205041 in words is "one hundred eleven billion, thirty-five million, two hundred five thousand, forty-one".
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