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11104130014110 = 2325746782145971
BaseRepresentation
bin1010000110010110000110…
…1110011001101110011110
31110022112200220122110211200
42201211201232121232132
52423412224240422420
635341100015100330
72224150456535310
oct241454156315636
943275626573750
1011104130014110
1135a12649aa811
1212b407a8116a6
13627165777213
142a562ad117b0
15143c9d29bb90
hexa1961b99b9e

11104130014110 has 192 divisors, whose sum is σ = 33106777726464. Its totient is φ = 2529512121600.

The previous prime is 11104130014069. The next prime is 11104130014141. The reversal of 11104130014110 is 1141003140111.

11104130014110 is a `hidden beast` number, since 1 + 110 + 413 + 0 + 0 + 141 + 1 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 241523425 + ... + 241569395.

It is an arithmetic number, because the mean of its divisors is an integer number (172431133992).

Almost surely, 211104130014110 is an apocalyptic number.

11104130014110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11104130014110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16553388863232).

11104130014110 is an abundant number, since it is smaller than the sum of its proper divisors (22002647712354).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11104130014110 is a wasteful number, since it uses less digits than its factorization.

11104130014110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47279 (or 47276 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 11104130014110 its reverse (1141003140111), we get a palindrome (12245133154221).

The spelling of 11104130014110 in words is "eleven trillion, one hundred four billion, one hundred thirty million, fourteen thousand, one hundred ten".