Base | Representation |
---|---|
bin | 1010000110010110001001… |
… | …1001001110101101110101 |
3 | 1110022112201200202212112000 |
4 | 2201211202121032231311 |
5 | 2423412240124204310 |
6 | 35341101055445513 |
7 | 2224150654135335 |
oct | 241454231165565 |
9 | 43275650685460 |
10 | 11104141241205 |
11 | 35a1270278901 |
12 | 12b4082526899 |
13 | 627167ba847c |
14 | 2a562c5d50c5 |
15 | 143c9e2684c0 |
hex | a196264eb75 |
11104141241205 has 32 divisors (see below), whose sum is σ = 20377492177920. Its totient is φ = 5731169670720.
The previous prime is 11104141241119. The next prime is 11104141241213. The reversal of 11104141241205 is 50214214140111.
11104141241205 is a `hidden beast` number, since 1 + 1 + 1 + 0 + 4 + 1 + 412 + 41 + 205 = 666.
11104141241205 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11104141241205 - 211 = 11104141239157 is a prime.
It is a super-3 number, since 3×111041412412053 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1326655462 + ... + 1326663831.
It is an arithmetic number, because the mean of its divisors is an integer number (636796630560).
Almost surely, 211104141241205 is an apocalyptic number.
11104141241205 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11104141241205 is a deficient number, since it is larger than the sum of its proper divisors (9273350936715).
11104141241205 is a wasteful number, since it uses less digits than its factorization.
11104141241205 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2653319338 (or 2653319332 counting only the distinct ones).
The product of its (nonzero) digits is 1280, while the sum is 27.
Adding to 11104141241205 its reverse (50214214140111), we get a palindrome (61318355381316).
The spelling of 11104141241205 in words is "eleven trillion, one hundred four billion, one hundred forty-one million, two hundred forty-one thousand, two hundred five".
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