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111043214003993 is a prime number
BaseRepresentation
bin11001001111111001000011…
…010100110100111100011001
3112120011121221111202001201112
4121033321003110310330121
5104023313000241111433
61032100314232230105
732250415234323455
oct3117710324647431
9476147844661645
10111043214003993
1132422187461977
1210554b0383b335
1349c643a45225b
141d5c73d747665
15cc874ebc8348
hex64fe43534f19

111043214003993 has 2 divisors, whose sum is σ = 111043214003994. Its totient is φ = 111043214003992.

The previous prime is 111043214003959. The next prime is 111043214004013. The reversal of 111043214003993 is 399300412340111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108059413796569 + 2983800207424 = 10395163^2 + 1727368^2 .

It is a cyclic number.

It is not a de Polignac number, because 111043214003993 - 210 = 111043214002969 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 111043214003993.

It is not a weakly prime, because it can be changed into another prime (111043214003093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55521607001996 + 55521607001997.

It is an arithmetic number, because the mean of its divisors is an integer number (55521607001997).

Almost surely, 2111043214003993 is an apocalyptic number.

It is an amenable number.

111043214003993 is a deficient number, since it is larger than the sum of its proper divisors (1).

111043214003993 is an equidigital number, since it uses as much as digits as its factorization.

111043214003993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 111043214003993 in words is "one hundred eleven trillion, forty-three billion, two hundred fourteen million, three thousand, nine hundred ninety-three".