Base | Representation |
---|---|
bin | 1010000110010110111001… |
… | …0111100111010000000011 |
3 | 1110022120020200210210100101 |
4 | 2201211232113213100003 |
5 | 2423413143042102003 |
6 | 35341133033503231 |
7 | 2224155643602643 |
oct | 241455627472003 |
9 | 43276220723311 |
10 | 11104342144003 |
11 | 35a1363718079 |
12 | 12b4119871b17 |
13 | 62719a6ba674 |
14 | 2a564b170523 |
15 | 143cb1c0011d |
hex | a196e5e7403 |
11104342144003 has 2 divisors, whose sum is σ = 11104342144004. Its totient is φ = 11104342144002.
The previous prime is 11104342143953. The next prime is 11104342144013. The reversal of 11104342144003 is 30044124340111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11104342144003 - 213 = 11104342135811 is a prime.
It is a super-2 number, since 2×111043421440032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11104342144013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552171072001 + 5552171072002.
It is an arithmetic number, because the mean of its divisors is an integer number (5552171072002).
Almost surely, 211104342144003 is an apocalyptic number.
11104342144003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11104342144003 is an equidigital number, since it uses as much as digits as its factorization.
11104342144003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 11104342144003 its reverse (30044124340111), we get a palindrome (41148466484114).
The spelling of 11104342144003 in words is "eleven trillion, one hundred four billion, three hundred forty-two million, one hundred forty-four thousand, three".
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