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11105000003 is a prime number
BaseRepresentation
bin10100101011110100…
…01101101001000011
31001122221000110011102
422111322031221003
5140220340000003
65033534405015
7542122641206
oct122572155103
931587013142
1011105000003
114789534959
12219b06076b
13107c8cbc26
14774c0393d
1544edd0588
hex295e8da43

11105000003 has 2 divisors, whose sum is σ = 11105000004. Its totient is φ = 11105000002.

The previous prime is 11104999987. The next prime is 11105000057. The reversal of 11105000003 is 30000050111.

11105000003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30000050111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11105000003 - 24 = 11104999987 is a prime.

It is not a weakly prime, because it can be changed into another prime (11105000063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552500001 + 5552500002.

It is an arithmetic number, because the mean of its divisors is an integer number (5552500002).

Almost surely, 211105000003 is an apocalyptic number.

11105000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11105000003 is an equidigital number, since it uses as much as digits as its factorization.

11105000003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 11.

Adding to 11105000003 its reverse (30000050111), we get a palindrome (41105050114).

The spelling of 11105000003 in words is "eleven billion, one hundred five million, three", and thus it is an aban number.