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11109994993 is a prime number
BaseRepresentation
bin10100101100011010…
…10001000111110001
31001200021102020000001
422112031101013301
5140223124314433
65034233430001
7542213253646
oct122615210761
931607366001
1011109994993
114791336749
1221a086b301
13108095a646
14775743dcd
1545056a57d
hex2963511f1

11109994993 has 2 divisors, whose sum is σ = 11109994994. Its totient is φ = 11109994992.

The previous prime is 11109994949. The next prime is 11109994999. The reversal of 11109994993 is 39949990111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10447292944 + 662702049 = 102212^2 + 25743^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11109994993 is a prime.

It is not a weakly prime, because it can be changed into another prime (11109994999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5554997496 + 5554997497.

It is an arithmetic number, because the mean of its divisors is an integer number (5554997497).

Almost surely, 211109994993 is an apocalyptic number.

It is an amenable number.

11109994993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11109994993 is an equidigital number, since it uses as much as digits as its factorization.

11109994993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 708588, while the sum is 55.

The spelling of 11109994993 in words is "eleven billion, one hundred nine million, nine hundred ninety-four thousand, nine hundred ninety-three".