Base | Representation |
---|---|
bin | 11001010000101101111100… |
… | …000011001000010101110011 |
3 | 112120101001112001001210110011 |
4 | 121100231330003020111303 |
5 | 104030230300030203021 |
6 | 1032142345134315351 |
7 | 32254465401350005 |
oct | 3120557403102563 |
9 | 476331461053404 |
10 | 111100000241011 |
11 | 32444277846271 |
12 | 10563b11358b57 |
13 | 49cb8ba132332 |
14 | 1d613a946c375 |
15 | cc9e7520ede1 |
hex | 650b7c0c8573 |
111100000241011 has 2 divisors, whose sum is σ = 111100000241012. Its totient is φ = 111100000241010.
The previous prime is 111100000240987. The next prime is 111100000241057. The reversal of 111100000241011 is 110142000001111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111100000241011 - 27 = 111100000240883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111100000240982 and 111100000241000.
It is not a weakly prime, because it can be changed into another prime (111100000248011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55550000120505 + 55550000120506.
It is an arithmetic number, because the mean of its divisors is an integer number (55550000120506).
Almost surely, 2111100000241011 is an apocalyptic number.
111100000241011 is a deficient number, since it is larger than the sum of its proper divisors (1).
111100000241011 is an equidigital number, since it uses as much as digits as its factorization.
111100000241011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 111100000241011 its reverse (110142000001111), we get a palindrome (221242000242122).
The spelling of 111100000241011 in words is "one hundred eleven trillion, one hundred billion, two hundred forty-one thousand, eleven".
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