Base | Representation |
---|---|
bin | 1010000110101011111110… |
… | …0111000000011100001011 |
3 | 1110100002212000020210102002 |
4 | 2201222333213000130023 |
5 | 2424011240011214011 |
6 | 35343510311301215 |
7 | 2224446105464531 |
oct | 241527747003413 |
9 | 43302760223362 |
10 | 11110000101131 |
11 | 35a37a7468aa8 |
12 | 12b523867a80b |
13 | 62788c957ca9 |
14 | 2a5a26784151 |
15 | 143ee37c1c3b |
hex | a1abf9c070b |
11110000101131 has 2 divisors, whose sum is σ = 11110000101132. Its totient is φ = 11110000101130.
The previous prime is 11110000101089. The next prime is 11110000101169. The reversal of 11110000101131 is 13110100001111.
11110000101131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (13110100001111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11110000101131 - 214 = 11110000084747 is a prime.
It is a super-2 number, since 2×111100001011312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11110000101181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555000050565 + 5555000050566.
It is an arithmetic number, because the mean of its divisors is an integer number (5555000050566).
Almost surely, 211110000101131 is an apocalyptic number.
11110000101131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110000101131 is an equidigital number, since it uses as much as digits as its factorization.
11110000101131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 11110000101131 its reverse (13110100001111), we get a palindrome (24220100102242).
The spelling of 11110000101131 in words is "eleven trillion, one hundred ten billion, one hundred one thousand, one hundred thirty-one".
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