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11110000999873 is a prime number
BaseRepresentation
bin1010000110101011111110…
…1010011011110111000001
31110100002212001221110020211
42201222333222123313001
52424011240223443443
635343510342434121
72224446116230006
oct241527752336701
943302761843224
1011110000999873
1135a37a7a22266
1212b5238a32941
1362788cbb10a9
142a5a269398ad
15143ee38ed19d
hexa1abfa9bdc1

11110000999873 has 2 divisors, whose sum is σ = 11110000999874. Its totient is φ = 11110000999872.

The previous prime is 11110000999817. The next prime is 11110000999921. The reversal of 11110000999873 is 37899900001111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9856033282624 + 1253967717249 = 3139432^2 + 1119807^2 .

It is an emirp because it is prime and its reverse (37899900001111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11110000999873 - 217 = 11110000868801 is a prime.

It is a super-2 number, since 2×111100009998732 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11110000997873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555000499936 + 5555000499937.

It is an arithmetic number, because the mean of its divisors is an integer number (5555000499937).

Almost surely, 211110000999873 is an apocalyptic number.

It is an amenable number.

11110000999873 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110000999873 is an equidigital number, since it uses as much as digits as its factorization.

11110000999873 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 122472, while the sum is 49.

The spelling of 11110000999873 in words is "eleven trillion, one hundred ten billion, nine hundred ninety-nine thousand, eight hundred seventy-three".