Base | Representation |
---|---|
bin | 1010000110101011111110… |
… | …1010110111010001000011 |
3 | 1110100002212002011011020112 |
4 | 2201222333222313101003 |
5 | 2424011240241042011 |
6 | 35343510345101535 |
7 | 2224446120205205 |
oct | 241527752672103 |
9 | 43302762134215 |
10 | 11110001112131 |
11 | 35a37a7a99639 |
12 | 12b5238a878ab |
13 | 62788cc2020c |
14 | 2a5a26968775 |
15 | 143ee392158b |
hex | a1abfab7443 |
11110001112131 has 2 divisors, whose sum is σ = 11110001112132. Its totient is φ = 11110001112130.
The previous prime is 11110001112073. The next prime is 11110001112143. The reversal of 11110001112131 is 13121110001111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11110001112131 - 210 = 11110001111107 is a prime.
It is a super-2 number, since 2×111100011121312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11110001112151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555000556065 + 5555000556066.
It is an arithmetic number, because the mean of its divisors is an integer number (5555000556066).
Almost surely, 211110001112131 is an apocalyptic number.
11110001112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110001112131 is an equidigital number, since it uses as much as digits as its factorization.
11110001112131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 14.
Adding to 11110001112131 its reverse (13121110001111), we get a palindrome (24231111113242).
The spelling of 11110001112131 in words is "eleven trillion, one hundred ten billion, one million, one hundred twelve thousand, one hundred thirty-one".
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