111100011313 has 2 divisors, whose sum is σ = 111100011314. Its totient is φ = 111100011312.

The previous prime is 111100011287. The next prime is 111100011349. The reversal of 111100011313 is 313110001111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85607737744 + 25492273569 = 292588^2 + 159663^2 .

It is an emirp because it is prime and its reverse (313110001111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111100011313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111100011293 and 111100011302.

It is not a weakly prime, because it can be changed into another prime (111100011713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55550005656 + 55550005657.

It is an arithmetic number, because the mean of its divisors is an integer number (55550005657).

Almost surely, 2^111100011313 is an apocalyptic number.

It is an amenable number.

111100011313 is a deficient number, since it is larger than the sum of its proper divisors (1).

111100011313 is an equidigital number, since it uses as much as digits as its factorization.

111100011313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 111100011313 its reverse (313110001111), we get a palindrome (424210012424).

The spelling of 111100011313 in words is "one hundred eleven billion, one hundred million, eleven thousand, three hundred thirteen".