11110010102083 has 2 divisors, whose sum is σ = 11110010102084. Its totient is φ = 11110010102082.

The previous prime is 11110010101999. The next prime is 11110010102101. The reversal of 11110010102083 is 38020101001111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11110010102083 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11110010102083.

It is not a weakly prime, because it can be changed into another prime (11110010102483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555005051041 + 5555005051042.

It is an arithmetic number, because the mean of its divisors is an integer number (5555005051042).

Almost surely, 2^{11110010102083} is an apocalyptic number.

11110010102083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110010102083 is an equidigital number, since it uses as much as digits as its factorization.

11110010102083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 11110010102083 its reverse (38020101001111), we get a palindrome (49130111103194).

The spelling of 11110010102083 in words is "eleven trillion, one hundred ten billion, ten million, one hundred two thousand, eighty-three".